So you have seen the above image by now, right?
Let me explain the above image in short.
AlH3 lewis structure has an Aluminum atom (Al) at the center which is surrounded by three Hydrogen atoms (H). There are 3 single bonds between the Aluminum atom (Al) and each Hydrogen atom (H).
If you haven’t understood anything from the above image of AlH3 lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of AlH3.
So let’s move to the steps of drawing the lewis structure of AlH3.
Steps of drawing AlH3 lewis structure
Step 1: Find the total valence electrons in AlH3 molecule
In order to find the total valence electrons in AlH3 molecule, first of all you should know the valence electrons present in aluminum atom as well as hydrogen atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)
Here, I’ll tell you how you can easily find the valence electrons of aluminum as well as hydrogen using a periodic table.
Total valence electrons in AlH3 molecule
→ Valence electrons given by aluminum atom:
Aluminum is a group 13 element on the periodic table. [1] Hence the valence electrons present in aluminum is 3.
You can see the 3 valence electrons present in the aluminum atom as shown in the above image.
→ Valence electrons given by hydrogen atom:
Hydrogen is group 1 element on the periodic table. [2] Hence the valence electron present in hydrogen is 1.
You can see that only 1 valence electron is present in the hydrogen atom as shown in the above image.
Hence,
Total valence electrons in AlH3 molecule = valence electrons given by 1 aluminum atom + valence electrons given by 3 hydrogen atoms = 3 + 1(3) = 6.
Step 2: Select the central atom
For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.
(Remember: If hydrogen is present in the given molecule, then always put hydrogen outside.)
Now here the given molecule is AlH3 and it contains aluminum atom (Al) and hydrogen atoms (H).
You can see the electronegativity values of aluminum atom (Al) and hydrogen atom (H) in the above periodic table.
If we compare the electronegativity values of aluminum (Al) and hydrogen (H) then the hydrogen atom is less electronegative. But as per the rule we have to keep hydrogen outside.
So here the aluminum atom (Al) is the center atom and the hydrogen atoms (H) are the outside atoms.
Step 3: Connect each atoms by putting an electron pair between them
Now in the AlH3 molecule, you have to put the electron pairs between the aluminum atom (Al) and hydrogen atoms (H).
This indicates that the aluminum (Al) and hydrogen (H) are chemically bonded with each other in a AlH3 molecule.
Step 4: Make the outer atoms stable
Now in this step, you have to check the stability of the outer atoms.
Here in the sketch of AlH3 molecule, you can see that the outer atoms are hydrogen atoms.
These outer hydrogen atoms are forming a duplet and hence they are stable.
Also, in step 1 we have calculated the total number of valence electrons present in the AlH3 molecule.
The NH3 molecule has a total 6 valence electrons and all these valence electrons are used in the above sketch of AlH3.
Hence there are no remaining electron pairs to be kept on the central atom.
So now let’s proceed to the next step.
Step 5: Check the stability of lewis structure
Now you have come to the final step in which you have to check the stability of lewis structure of AlH3.
The stability of lewis structure can be checked by using a concept of formal charge.
In short, now you have to find the formal charge on aluminum (Al) atom as well as hydrogen (H) atoms present in the AlH3 molecule.
For calculating the formal charge, you have to use the following formula;
Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons
You can see the number of bonding electrons and nonbonding electrons for each atom of AlH3 molecule in the image given below.
For Aluminum (Al) atom:
Valence electrons = 3 (because aluminum is in group 13)
Bonding electrons = 6
Nonbonding electrons = 0
For Hydrogen (H) atom:
Valence electron = 1 (because hydrogen is in group 1)
Bonding electrons = 2
Nonbonding electrons = 0
Formal charge | = | Valence electrons | – | (Bonding electrons)/2 | – | Nonbonding electrons | ||
Al | = | 3 | – | 6/2 | – | 0 | = | 0 |
H | = | 1 | – | 2/2 | – | 0 | = | 0 |
From the above calculations of formal charge, you can see that the aluminum (Al) atom as well as hydrogen (H) atom has a “zero” formal charge.
This indicates that the above lewis structure of AlH3 is stable and there is no further change in the above structure of AlH3.
In the above lewis dot structure of AlH3, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of AlH3.
I hope you have completely understood all the above steps.
For more practice and better understanding, you can try other lewis structures listed below.
Try (or at least See) these lewis structures for better understanding:
SbF3 Lewis Structure | Cl3- Lewis Structure |
PCl2- Lewis Structure | AsO2- Lewis Structure |
SBr4 Lewis Structure | BrCl5 Lewis Structure |
Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. He is a founder of Pediabay and is passionate about helping students through his easily digestible explanations.
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