H2Te Lewis Structure in 6 Steps (With Images)

So you have seen the above image by now, right?

Let me explain the above image in short.

H2Te lewis structure has a Tellurium atom (Te) at the center which is surrounded by two Hydrogen atoms (H). There are 2 single bonds between the Tellurium atom (Te) and each Hydrogen atom (H). There are 2 lone pairs on the Tellurium atom (Te).

If you haven’t understood anything from the above image of H2Te lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of H2Te.

So let’s move to the steps of drawing the lewis structure of H2Te.

Steps of drawing H2Te lewis structure

Step 1: Find the total valence electrons in H2Te molecule

In order to find the total valence electrons in a H2Te molecule, first of all you should know the valence electrons present in hydrogen atom as well as tellurium atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)

Here, I’ll tell you how you can easily find the valence electrons of hydrogen as well as tellurium using a periodic table.

Total valence electrons in H2Te molecule

→ Valence electrons given by hydrogen atom:

Hydrogen is group 1 element on the periodic table. ^[1] Hence the valence electron present in hydrogen is 1.

You can see that only 1 valence electron is present in the hydrogen atom as shown in the above image.

→ Valence electrons given by tellurium atom:

Tellurium is a group 16 element on the periodic table. ^[2] Hence the valence electrons present in tellurium is 6.

You can see the 6 valence electrons present in the tellurium atom as shown in the above image.

Hence, 

Total valence electrons in H2Te molecule = valence electrons given by 2 hydrogen atoms + valence electrons given by 1 tellurium atom = 1(2) + 6 = 8.

Step 2: Select the central atom

For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.

(Remember: If hydrogen is present in the given molecule, then always put hydrogen outside.)

Now here the given molecule is H2Te and it contains hydrogen atoms (H) and tellurium atom (Te).

You can see the electronegativity values of hydrogen atom (H) and tellurium atom (Te) in the above periodic table.

If we compare the electronegativity values of hydrogen (H) and tellurium (Te) then the hydrogen atom is less electronegative. But as per the rule we have to keep hydrogen outside.

So here the tellurium atom (Te) is the center atom and the hydrogen atoms (H) are the outside atoms.

Step 3: Connect each atoms by putting an electron pair between them

Now in the H2Te molecule, you have to put the electron pairs between the tellurium atom (Te) and hydrogen atoms (H).

This indicates that the tellurium (Te) and hydrogen (H) are chemically bonded with each other in a H2Te molecule.

Step 4: Make the outer atoms stable. Place the remaining valence electrons pair on the central atom.

Now in this step, you have to check the stability of the outer atoms.

Here in the sketch of H2Te molecule, you can see that the outer atoms are hydrogen atoms.

These outer hydrogen atoms are forming a duplet and hence they are stable. 

Also, in step 1 we have calculated the total number of valence electrons present in the H2Te molecule.

The H2Te molecule has a total 8 valence electrons and out of these, only 4 valence electrons are used in the above sketch.

So the number of electrons which are left = 8 – 4 = 4.

You have to put these 4 electrons on the central tellurium atom in the above sketch of H2Te molecule.

Now let’s proceed to the next step.

Step 5: Check the octet on the central atom

In this step, you have to check whether the central tellurium atom (Te) is stable or not.

In order to check the stability of the central tellurium (Te) atom, we have to check whether it is forming an octet or not.

You can see from the above picture that the tellurium atom is forming an octet. That means it has 8 electrons.

And hence the central tellurium atom is stable.

Now let’s proceed to the final step to check whether the lewis structure of H2Te is stable or not.

Step 6: Check the stability of lewis structure

Now you have come to the final step in which you have to check the stability of lewis structure of H2Te.

The stability of lewis structure can be checked by using a concept of formal charge.

In short, now you have to find the formal charge on hydrogen (H) atoms as well as tellurium (Te) atom present in the H2Te molecule.

For calculating the formal charge, you have to use the following formula;

Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons

You can see the number of bonding electrons and nonbonding electrons for each atom of H2Te molecule in the image given below.

For Hydrogen (H) atom:
Valence electron = 1 (because hydrogen is in group 1)
Bonding electrons = 2
Nonbonding electrons = 0

For Tellurium (Te) atom:
Valence electrons = 6 (because tellurium is in group 16)
Bonding electrons = 4
Nonbonding electrons = 4

From the above calculations of formal charge, you can see that the hydrogen (H) atoms as well as tellurium (Te) atom have a “zero” formal charge.

This indicates that the above lewis structure of H2Te is stable and there is no further change in the above structure of H2Te.

In the above lewis dot structure of H2Te, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of H2Te.

I hope you have completely understood all the above steps.

For more practice and better understanding, you can try other lewis structures listed below.

Try (or at least See) these lewis structures for better understanding:

About author

Jay Rana

Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. He is a founder of Pediabay and is passionate about helping students through his easily digestible explanations.

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