HF Lewis Structure in 6 Steps (With Images

So you have seen the above image by now, right?

Let me explain the above image in short.

HF (hydrogen fluoride) lewis structure has one Hydrogen atom (H) and one Fluorine atom (F) which contain a single bond between them. There are 3 lone pairs on the Fluorine atom (F).

If you haven’t understood anything from the above image of HF (hydrogen fluoride) lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of HF.

So let’s move to the steps of drawing the lewis structure of HF.

Steps of drawing HF lewis structure

Step 1: Find the total valence electrons in HF molecule

In order to find the total valence electrons in HF (hydrogen fluoride) molecule, first of all you should know the valence electrons present in a single hydrogen atom as well as fluorine atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)

Here, I’ll tell you how you can easily find the valence electrons of hydrogen as well as fluorine using a periodic table.

Total valence electrons in HF molecule

→ Valence electrons given by hydrogen atom:

Hydrogen is group 1 element on the periodic table. ^[1] Hence the valence electron present in hydrogen is 1.

You can see that only 1 valence electron is present in the hydrogen atom as shown in the above image.

→ Valence electrons given by fluorine atom:

Fluorine is group 17 element on the periodic table. ^[2] Hence the valence electron present in fluorine is 7.

You can see the 7 valence electrons present in the fluorine atom as shown in the above image.

Hence, 

Total valence electrons in HF molecule = valence electrons given by 1 hydrogen atom + valence electrons given by 1 fluorine atom = 1 + 7 = 8.

Step 2: Select the central atom

For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.

Now the given molecule is HF (hydrogen fluorine). It has only two atoms, so you can select any of the atoms as a center atom.

Let’s assume the fluorine atom as a central atom (Because we have to keep hydrogen outside in any lewis structure).

Step 3: Connect each atoms by putting an electron pair between them

Now in the HF molecule, you have to put the electron pairs between the hydrogen atom (H) and fluorine atom (F).

This indicates that the hydrogen (H) atom and fluorine (F) atom are chemically bonded with each other in a HF molecule.

Step 4: Make the outer atoms stable. Place the remaining valence electrons pair on the central atom.

Now in this step, you have to check the stability of the outer atom.

Here in the sketch of HF molecule, we have assumed the fluorine atom as a center atom. So the hydrogen is the outer atom.

Hence you have to make the hydrogen atom stable.

You can see in the below image that the hydrogen atom is forming a duplet and hence it is stable.

Also, in step 1 we have calculated the total number of valence electrons present in the HF molecule.

The HF molecule has a total 8 valence electrons and out of these, only 2 valence electrons are used in the above sketch.

So the number of electrons which are left = 8 – 2 = 6.

You have to put these 6 electrons on the fluorine atom in the above sketch of HF molecule.

Now let’s proceed to the next step.

Step 5: Check the octet on the central atom

In this step, you have to check whether the central fluorine atom (F) is stable or not.

In order to check the stability of the central fluorine (F) atom, we have to check whether it is forming an octet or not.

You can see from the above picture that the fluorine atom is forming an octet. That means it has 8 electrons.

And hence the central fluorine atom is stable.

Now let’s proceed to the final step to check whether the lewis structure of HF is stable or not.

Step 6: Check the stability of lewis structure

Now you have come to the final step in which you have to check the stability of lewis structure of HF.

The stability of lewis structure can be checked by using a concept of formal charge.

In short, now you have to find the formal charge on hydrogen (H) atom as well as fluorine (F) atoms present in the HF molecule.

For calculating the formal charge, you have to use the following formula;

Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons

You can see the number of bonding electrons and nonbonding electrons for each atom of HF molecule in the image given below.

For Hydrogen (H) atom:
Valence electron = 1 (because hydrogen is in group 1)
Bonding electrons = 2
Nonbonding electrons = 0

For Fluorine (F) atom:
Valence electron = 7 (because fluorine is in group 17)
Bonding electrons = 2
Nonbonding electrons = 6

From the above calculations of formal charge, you can see that the hydrogen (H) atom as well as fluorine (F) atom has a “zero” formal charge.

This indicates that the above lewis structure of HF is stable and there is no further change in the above structure of HF.

In the above lewis dot structure of HF, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of HF.

I hope you have completely understood all the above steps.

For more practice and better understanding, you can try other lewis structures listed below.

Try (or at least See) these lewis structures for better understanding:

About author

Jay Rana

Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. He is a founder of Pediabay and is passionate about helping students through his easily digestible explanations.

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