C2HCl Lewis Structure in 6 Steps (With Images)

So you have seen the above image by now, right?

Let me explain the above image in short.

C2HCl lewis structure has a triple bond between the Carbon-Carbon atoms and a single bond between the Carbon-Hydrogen atoms and Carbon-Chlorine atoms. There are 3 lone pairs on Chlorine atom (Cl).

If you haven’t understood anything from the above image of C2HCl lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of C2HCl.

So let’s move to the steps of drawing the lewis structure of C2HCl.

Steps of drawing C2HCl lewis structure

Step 1: Find the total valence electrons in C2HCl molecule

In order to find the total valence electrons in a C2HCl molecule, first of all you should know the valence electrons present in carbon atom, hydrogen atom as well as chlorine atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)

Here, I’ll tell you how you can easily find the valence electrons of carbon, hydrogen as well as chlorine using a periodic table.

Total valence electrons in C2HCl molecule

→ Valence electrons given by carbon atom:

Carbon is group 14 element on the periodic table. ^[1] Hence the valence electrons present in carbon is 4.

You can see the 4 valence electrons present in the carbon atom as shown in the above image.

→ Valence electrons given by hydrogen atom:

Hydrogen is group 1 element on the periodic table. ^[2] Hence the valence electron present in hydrogen is 1.

You can see that only 1 valence electron is present in the hydrogen atom as shown in the above image.

→ Valence electrons given by chlorine atom:

Chlorine is group 17 element on the periodic table. ^[3] Hence the valence electrons present in chlorine is 7.

You can see the 7 valence electrons present in the chlorine atom as shown in the above image.

Hence, 

Total valence electrons in C2HCl molecule = valence electrons given by 2 carbon atoms + valence electrons given by 1 hydrogen atom + valence electrons given by 1 chlorine atom = 4(2) + 1 + 7 = 16.

Step 2: Select the central atom

For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.

(Remember: If hydrogen is present in the given molecule, then always put hydrogen outside.)

Now here the given molecule is C2HCl and it contains carbon atoms (C), hydrogen atom (H) and chlorine atom (Cl).

So as per the rule we have to keep hydrogen outside.

Now, you can see the electronegativity values of carbon atom (C) and chlorine atom (Cl) in the above periodic table.

If we compare the electronegativity values of carbon (C) and chlorine (Cl) then the carbon atom is less electronegative.

So here the carbon atom (C) is the center atom and the chlorine atom (Cl) is the outside atom.

Step 3: Connect each atoms by putting an electron pair between them

Now in the C2HCl molecule, you have to put the electron pairs between the carbon (C), hydrogen (H) and chlorine (Cl) atoms.

This indicates that these atoms are chemically bonded with each other in a C2HCl molecule.

Step 4: Make the outer atoms stable

Now in this step, you have to check the stability of the outer atoms.

Here in the sketch of C2HCl molecule, you can see that the outer atoms are hydrogen atom and chlorine atom.

These hydrogen atom and chlorine atom are forming a duplet and octet respectively and hence they are stable.

Also, in step 1 we have calculated the total number of valence electrons present in the C2HCl molecule.

The C2HCl molecule has a total 16 valence electrons and out of these, only 12 valence electrons are used in the above sketch.

So the number of electrons which are left = 16 – 12 = 4.

You have to put these 4 electrons on the carbon atoms in the above sketch of C2HCl molecule.

Now let’s proceed to the next step.

Step 5: Check the octet on the central atom. If it does not have octet, then convert the lone pair into a double bond or triple bond.

In this step, you have to check whether the central carbon atoms (C) are stable or not.

In order to check the stability of the central carbon (C) atoms, we have to check whether they are forming an octet or not.

Unfortunately, both the carbon atoms are not forming an octet here. Both the carbon atoms have only 6 electrons and they are unstable.

Now to make the carbon atom stable, you have to convert the lone pair into a double bond so that the carbon atom can have 8 electrons (i.e octet).

But after converting one electron pair, one carbon atom is forming an octet but the other carbon atom is still not forming an octet as it has only 6 electrons.

So again we have to convert one more electron pair to form a triple bond.

After converting this electron pair into a triple bond, the central carbon atom will get 2 more electrons and thus its total electrons will become 8.

You can see from the above picture that both the carbon atoms are forming an octet.

And hence these carbon atoms are stable.

Now let’s proceed to the final step to check whether the lewis structure of C2HCl is stable or not.

Step 6: Check the stability of lewis structure

Now you have come to the final step in which you have to check the stability of lewis structure of C2HCl.

The stability of lewis structure can be checked by using a concept of formal charge.

In short, now you have to find the formal charge on carbon (C) atom, hydrogen (H) atom as well as chlorine (Cl) atom present in the C2HCl molecule.

For calculating the formal charge, you have to use the following formula;

Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons

You can see the number of bonding electrons and nonbonding electrons for each atom of C2HCl molecule in the image given below.

For Carbon (C) atom:
Valence electrons = 4 (because carbon is in group 14)
Bonding electrons = 8
Nonbonding electrons = 0

For Hydrogen (H) atom:
Valence electron = 1 (because hydrogen is in group 1)
Bonding electrons = 2
Nonbonding electrons = 0

For Chlorine (Cl) atom:
Valence electrons = 7 (because chlorine is in group 17)
Bonding electrons = 2
Nonbonding electrons = 6

Formal charge	=	Valence electrons	–	(Bonding electrons)/2	–	Nonbonding electrons
C	=	4	–	8/2	–	0	=	0
H	=	1	–	2/2	–	0	=	0
Cl	=	7	–	2/2	–	6	=	0

From the above calculations of formal charge, you can see that the carbon (C) atoms, hydrogen (H) atom as well as chlorine (Cl) atom have a “zero” formal charge.

This indicates that the above lewis structure of C2HCl is stable and there is no further change in the above structure of C2HCl.

In the above lewis dot structure of C2HCl, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of C2HCl.

I hope you have completely understood all the above steps.

For more practice and better understanding, you can try other lewis structures listed below.

Try (or at least See) these lewis structures for better understanding:

BrCl3 Lewis Structure	NO2Cl Lewis Structure
TeF4 Lewis Structure	ClF Lewis Structure
SO Lewis Structure	XeCl2 Lewis Structure