PBr5 Lewis Structure in 5 Steps (With Images)

So you have seen the above image by now, right?

Let me explain the above image in short.

PBr5 lewis structure has a Phosphorus atom (P) at the center which is surrounded by five Bromine atoms (Br). There are 5 single bonds between the Phosphorus atom (P) and each Bromine atom (Br).

If you haven’t understood anything from the above image of PBr5 (phosphorus pentabromide) lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of PBr5.

So let’s move to the steps of drawing the lewis structure of PBr5.

Steps of drawing PBr5 lewis structure

Step 1: Find the total valence electrons in PBr5 molecule

In order to find the total valence electrons in a PBr5 (phosphorus pentabromide) molecule, first of all you should know the valence electrons present in phosphorus atom as well as bromine atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)

Here, I’ll tell you how you can easily find the valence electrons of phosphorus as well as bromine using a periodic table.

Total valence electrons in PBr5 molecule

→ Valence electrons given by phosphorus atom:

Phosphorus is group 15 element on the periodic table. ^[1] Hence the valence electrons present in phosphorus is 5.

You can see the 5 valence electrons present in the phosphorus atom as shown in the above image.

→ Valence electrons given by bromine atom:

Bromine is a group 17 element on the periodic table. ^[2] Hence the valence electrons present in bromine is 7.

You can see the 7 valence electrons present in the bromine atom as shown in the above image.

Hence, 

Total valence electrons in PBr5 molecule = valence electrons given by 1 phosphorus atom + valence electrons given by 5 bromine atoms = 5 + 7(5) = 40.

Step 2: Select the central atom

For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.

Now here the given molecule is PBr5 (phosphorus pentabromide) and it contains phosphorus atom (P) and bromine atoms (Br).

You can see the electronegativity values of phosphorus atom (P) and bromine atom (Br) in the above periodic table.

If we compare the electronegativity values of phosphorus (P) and bromine (Br) then the phosphorus atom is less electronegative.

So here the phosphorus atom (P) is the center atom and the bromine atoms (Br) are the outside atoms.

Step 3: Connect each atoms by putting an electron pair between them

Now in the PBr5 molecule, you have to put the electron pairs between the phosphorus atom (P) and bromine atoms (Br).

This indicates that the phosphorus (P) and bromine (Br) are chemically bonded with each other in a PBr5 molecule.

Step 4: Make the outer atoms stable

Now in this step, you have to check the stability of the outer atoms.

Here in the sketch of PBr5 molecule, you can see that the outer atoms are bromine atoms.

These outer bromine atoms are forming an octet and hence they are stable.

Also, in step 1 we have calculated the total number of valence electrons present in the PBr5 molecule.

The PBr5 molecule has a total 40 valence electrons and all these valence electrons are used in the above sketch of PBr5.

Hence there are no remaining electron pairs to be kept on the central atom. 

So now let’s proceed to the next step.

Step 5: Check the stability of lewis structure

Now you have come to the final step in which you have to check the stability of lewis structure of PBr5.

The stability of lewis structure can be checked by using a concept of formal charge.

In short, now you have to find the formal charge on phosphorus (P) atom as well as bromine (Br) atoms present in the PBr5 molecule.

For calculating the formal charge, you have to use the following formula;

Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons

You can see the number of bonding electrons and nonbonding electrons for each atom of PBr5 molecule in the image given below.

For Phosphorus (P) atom:
Valence electrons = 5 (because phosphorus is in group 15)
Bonding electrons = 10
Nonbonding electrons = 0

For Bromine (Br) atom:
Valence electrons = 7 (because bromine is in group 17)
Bonding electrons = 2
Nonbonding electrons = 6

Formal charge	=	Valence electrons	–	(Bonding electrons)/2	–	Nonbonding electrons
P	=	5	–	10/2	–	0	=	0
Br	=	7	–	2/2	–	6	=	0

From the above calculations of formal charge, you can see that the phosphorus (P) atom as well as bromine (Br) atom has a “zero” formal charge.

This indicates that the above lewis structure of PBr5 is stable and there is no further change in the above structure of PBr5.

In the above lewis dot structure of PBr5, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of PBr5.

I hope you have completely understood all the above steps.

For more practice and better understanding, you can try other lewis structures listed below.

Try (or at least See) these lewis structures for better understanding:

OCS Lewis Structure	Br3- Lewis Structure
H3O+ Lewis Structure	CH3NO2 Lewis Structure
AsH3 Lewis Structure	SeF6 Lewis Structure