S2O Lewis Structure in 6 Steps (With Images)

So you have seen the above image by now, right?

Let me explain the above image in short.

S2O lewis structure has a Sulfur atom (S) at the center which is surrounded by one Oxygen atom (O) and other Sulfur atom (S). There are double bonds between the Sulfur-Sulfur atoms and Sulfur-Oxygen atoms. There is 1 lone pair on the central Sulfur atom (S) and 2 lone pairs on the Oxygen atom (O) and outer Sulfur atom (S).

If you haven’t understood anything from the above image of S2O lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of S2O.

So let’s move to the steps of drawing the lewis structure of S2O.

Steps of drawing S2O lewis structure

Step 1: Find the total valence electrons in S2O molecule

In order to find the total valence electrons in S2O molecule, first of all you should know the valence electrons present in sulfur atom as well as oxygen atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)

Here, I’ll tell you how you can easily find the valence electrons of sulfur as well as oxygen using a periodic table.

Total valence electrons in S2O molecule

→ Valence electrons given by sulfur atom:

Sulfur is a group 16 element on the periodic table. ^[1] Hence the valence electrons present in sulfur is 6.

You can see the 6 valence electrons present in the sulfur atom as shown in the above image.

→ Valence electrons given by oxygen atom:

Oxygen is group 16 element on the periodic table. ^[2] Hence the valence electrons present in oxygen is 6.

You can see the 6 valence electrons present in the oxygen atom as shown in the above image.

Hence, 

Total valence electrons in S2O molecule = valence electrons given by 2 sulfur atoms + valence electrons given by 1 oxygen atom = 6(2) + 6 = 18.

Step 2: Select the central atom

For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.

Now here the given molecule is S2O and it contains sulfur atoms (S) and oxygen atom (O).

You can see the electronegativity values of sulfur atom (S) and oxygen atom (O) in the above periodic table.

If we compare the electronegativity values of sulfur (S) and oxygen (O) then the sulfur atom is less electronegative.

So here, one of the sulfur atoms (S) is the center atom and the oxygen atom (O) and other sulfur atom (S) are the outside atoms.

Step 3: Connect each atoms by putting an electron pair between them

Now in the S2O molecule, you have to put the electron pairs between the sulfur atom (S) and oxygen atoms (O).

This indicates that these atoms are chemically bonded with each other in a S2O molecule.

Step 4: Make the outer atoms stable. Place the remaining valence electrons pair on the central atom.

Now in this step, you have to check the stability of the outer atoms.

Here in the sketch of S2O molecule, you can see that the outer atoms are oxygen atom and sulfur atom.

These outer oxygen and sulfur atoms are forming an octet and hence they are stable. 

Also, in step 1 we have calculated the total number of valence electrons present in the S2O molecule.

The S2O molecule has a total 18 valence electrons and out of these, only 16 valence electrons are used in the above sketch.

So the number of electrons which are left = 18 – 16 = 2.

You have to put these 2 electrons on the central sulfur atom in the above sketch of S2O molecule.

Now let’s proceed to the next step.

Step 5: Check the octet on the central atom. If it does not have octet, then shift the lone pair to form a double bond or triple bond.

In this step, you have to check whether the central sulfur atom (S) is stable or not.

In order to check the stability of the central sulfur (S) atom, we have to check whether it is forming an octet or not.

Unfortunately, the sulfur atom is not forming an octet here. Sulfur has only 6 electrons and it is unstable.

Now to make this sulfur atom stable, you have to shift the electron pair from the outer sulfur atom so that the central sulfur atom can have 8 electrons (i.e octet).

After shifting this electron pair, the central sulfur atom will get 2 more electrons and thus its total electrons will become 8.

You can see from the above picture that the central sulfur atom is forming an octet as it has 8 electrons.

Now let’s proceed to the final step to check whether the lewis structure of S2O is stable or not.

Step 6: Check the stability of lewis structure

Now you have come to the final step in which you have to check the stability of lewis structure of S2O.

The stability of lewis structure can be checked by using a concept of formal charge.

In short, now you have to find the formal charge on sulfur (S) atoms as well as oxygen (O) atom present in the S2O molecule.

For calculating the formal charge, you have to use the following formula;

Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons

You can see the number of bonding electrons and nonbonding electrons for each atom of S2O molecule in the image given below.

For central Sulfur (S) atom:
Valence electrons = 6 (because sulfur is in group 16)
Bonding electrons = 6
Nonbonding electrons = 2

For outer Sulfur (S) atom:
Valence electrons = 6 (because sulfur is in group 16)
Bonding electrons = 4
Nonbonding electrons = 4

For Oxygen (O) atom:
Valence electrons = 6 (because oxygen is in group 16)
Bonding electrons = 4
Nonbonding electrons = 6

Formal charge	=	Valence electrons	–	(Bonding electrons)/2	–	Nonbonding electrons
S (central)	=	6	–	6/2	–	2	=	+1
S (outer)	=	6	–	4/2	–	4	=	0
O	=	6	–	2/2	–	6	=	-1

From the above calculations of formal charge, you can see that the central sulfur (S) atom has +1 charge and the oxygen (O) atom has -1 charge.

Because of this reason, the above obtained lewis structure of S2O is not stable. 

So we have to minimize these charges by shifting the electron pairs towards the sulfur atom.

After shifting the electron pair from oxygen atom to sulfur atom, the lewis structure of S2O becomes more stable.

In the above lewis dot structure of S2O, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of S2O.

I hope you have completely understood all the above steps.

For more practice and better understanding, you can try other lewis structures listed below.

Try (or at least See) these lewis structures for better understanding:

BrCl3 Lewis Structure	NO2Cl Lewis Structure
TeF4 Lewis Structure	ClF Lewis Structure
SO Lewis Structure	XeCl2 Lewis Structure