So you have seen the above image by now, right?
Let me explain the above image in short.
TeCl4 lewis structure has a Tellurium atom (Te) at the center which is surrounded by four Chlorine atoms (Cl). There are 4 single bonds between the Tellurium atom (Te) and each Chlorine atom (Cl). There is 1 lone pair on the Tellurium atom (Te) and 3 lone pairs on all the four Chlorine atoms (Cl).
If you haven’t understood anything from the above image of TeCl4 lewis structure, then just stick with me and you will get the detailed step by step explanation on drawing a lewis structure of TeCl4.
So let’s move to the steps of drawing the lewis structure of TeCl4.
Steps of drawing TeCl4 lewis structure
Step 1: Find the total valence electrons in TeCl4 molecule
In order to find the total valence electrons in a TeCl4 molecule, first of all you should know the valence electrons present in tellurium atom as well as chlorine atom.
(Valence electrons are the electrons that are present in the outermost orbit of any atom.)
Here, I’ll tell you how you can easily find the valence electrons of tellurium as well as chlorine using a periodic table.
Total valence electrons in TeCl4 molecule
→ Valence electrons given by tellurium atom:
Tellurium is a group 16 element on the periodic table. [1] Hence the valence electrons present in tellurium is 6.
You can see the 6 valence electrons present in the tellurium atom as shown in the above image.
→ Valence electrons given by chlorine atom:
Chlorine is group 17 element on the periodic table. [2] Hence the valence electrons present in chlorine is 7.
You can see the 7 valence electrons present in the chlorine atom as shown in the above image.
Hence,
Total valence electrons in TeCl4 molecule = valence electrons given by 1 tellurium atom + valence electrons given by 4 chlorine atoms = 6 + 7(4) = 34.
Step 2: Select the central atom
For selecting the center atom, you have to remember that the atom which is less electronegative remains at the center.
Now here the given molecule is TeCl4 and it contains tellurium atom (Te) and chlorine atoms (Cl).
You can see the electronegativity values of tellurium atom (Te) and chlorine atom (Cl) in the above periodic table.
If we compare the electronegativity values of tellurium (Te) and chlorine (Cl) then the tellurium atom is less electronegative.
So here the tellurium atom (Te) is the center atom and the chlorine atoms (Cl) are the outside atoms.
Step 3: Connect each atoms by putting an electron pair between them
Now in the TeCl4 molecule, you have to put the electron pairs between the tellurium atom (Te) and chlorine atoms (Cl).
This indicates that the tellurium (Te) and chlorine (Cl) are chemically bonded with each other in a TeCl4 molecule.
Step 4: Make the outer atoms stable
Now in this step, you have to check the stability of the outer atoms.
Here in the sketch of TeCl4 molecule, you can see that the outer atoms are chlorine atoms.
These outer chlorine atoms are forming an octet and hence they are stable.
Also, in step 1 we have calculated the total number of valence electrons present in the TeCl4 molecule.
The TeCl4 molecule has a total 34 valence electrons and out of these, only 32 valence electrons are used in the above sketch.
So the number of electrons which are left = 34 – 32 = 2.
You have to put these 2 electrons on the central tellurium atom in the above sketch of TeCl4 molecule.
Now let’s proceed to the next step.
Step 5: Check the stability of lewis structure
Now you have come to the final step in which you have to check the stability of lewis structure of TeCl4.
The stability of lewis structure can be checked by using a concept of formal charge.
In short, now you have to find the formal charge on tellurium (Te) atom as well as chlorine (Cl) atoms present in the TeCl4 molecule.
For calculating the formal charge, you have to use the following formula;
Formal charge = Valence electrons – (Bonding electrons)/2 – Nonbonding electrons
You can see the number of bonding electrons and nonbonding electrons for each atom of TeCl4 molecule in the image given below.
For Tellurium (Te) atom:
Valence electrons = 6 (because tellurium is in group 16)
Bonding electrons = 8
Nonbonding electrons = 2
For Chlorine (Cl) atom:
Valence electron = 7 (because chlorine is in group 17)
Bonding electrons = 2
Nonbonding electrons = 6
Formal charge | = | Valence electrons | – | (Bonding electrons)/2 | – | Nonbonding electrons | ||
Te | = | 6 | – | 8/2 | – | 2 | = | 0 |
Cl | = | 7 | – | 2/2 | – | 6 | = | 0 |
From the above calculations of formal charge, you can see that the tellurium (Te) atom as well as chlorine (Cl) atom has a “zero” formal charge.
This indicates that the above lewis structure of TeCl4 is stable and there is no further change in the above structure of TeCl4.
In the above lewis dot structure of TeCl4, you can also represent each bonding electron pair (:) as a single bond (|). By doing so, you will get the following lewis structure of TeCl4.
I hope you have completely understood all the above steps.
For more practice and better understanding, you can try other lewis structures listed below.
Try (or at least See) these lewis structures for better understanding:
XeF6 Lewis Structure | N2O3 Lewis Structure |
SnCl2 Lewis Structure | HOCN Lewis Structure |
NHF2 Lewis Structure | BrCN Lewis Structure |
Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. He is a founder of Pediabay and is passionate about helping students through his easily digestible explanations.
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